Optimal. Leaf size=115 \[ -\frac{a^4}{4 d (a-a \cos (c+d x))^2}-\frac{5 a^3}{4 d (a-a \cos (c+d x))}+\frac{a^2 \sec (c+d x)}{d}+\frac{17 a^2 \log (1-\cos (c+d x))}{8 d}-\frac{2 a^2 \log (\cos (c+d x))}{d}-\frac{a^2 \log (\cos (c+d x)+1)}{8 d} \]
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Rubi [A] time = 0.171222, antiderivative size = 115, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.19, Rules used = {3872, 2836, 12, 88} \[ -\frac{a^4}{4 d (a-a \cos (c+d x))^2}-\frac{5 a^3}{4 d (a-a \cos (c+d x))}+\frac{a^2 \sec (c+d x)}{d}+\frac{17 a^2 \log (1-\cos (c+d x))}{8 d}-\frac{2 a^2 \log (\cos (c+d x))}{d}-\frac{a^2 \log (\cos (c+d x)+1)}{8 d} \]
Antiderivative was successfully verified.
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Rule 3872
Rule 2836
Rule 12
Rule 88
Rubi steps
\begin{align*} \int \csc ^5(c+d x) (a+a \sec (c+d x))^2 \, dx &=\int (-a-a \cos (c+d x))^2 \csc ^5(c+d x) \sec ^2(c+d x) \, dx\\ &=\frac{a^5 \operatorname{Subst}\left (\int \frac{a^2}{(-a-x)^3 x^2 (-a+x)} \, dx,x,-a \cos (c+d x)\right )}{d}\\ &=\frac{a^7 \operatorname{Subst}\left (\int \frac{1}{(-a-x)^3 x^2 (-a+x)} \, dx,x,-a \cos (c+d x)\right )}{d}\\ &=\frac{a^7 \operatorname{Subst}\left (\int \left (\frac{1}{8 a^5 (a-x)}+\frac{1}{a^4 x^2}-\frac{2}{a^5 x}+\frac{1}{2 a^3 (a+x)^3}+\frac{5}{4 a^4 (a+x)^2}+\frac{17}{8 a^5 (a+x)}\right ) \, dx,x,-a \cos (c+d x)\right )}{d}\\ &=-\frac{a^4}{4 d (a-a \cos (c+d x))^2}-\frac{5 a^3}{4 d (a-a \cos (c+d x))}+\frac{17 a^2 \log (1-\cos (c+d x))}{8 d}-\frac{2 a^2 \log (\cos (c+d x))}{d}-\frac{a^2 \log (1+\cos (c+d x))}{8 d}+\frac{a^2 \sec (c+d x)}{d}\\ \end{align*}
Mathematica [A] time = 1.51333, size = 103, normalized size = 0.9 \[ -\frac{a^2 (\cos (c+d x)+1)^2 \sec ^4\left (\frac{1}{2} (c+d x)\right ) \left (\csc ^4\left (\frac{1}{2} (c+d x)\right )+10 \csc ^2\left (\frac{1}{2} (c+d x)\right )+4 \left (-4 \sec (c+d x)-17 \log \left (\sin \left (\frac{1}{2} (c+d x)\right )\right )+\log \left (\cos \left (\frac{1}{2} (c+d x)\right )\right )+8 \log (\cos (c+d x))\right )\right )}{64 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.072, size = 85, normalized size = 0.7 \begin{align*}{\frac{{a}^{2}\sec \left ( dx+c \right ) }{d}}-{\frac{{a}^{2}\ln \left ( 1+\sec \left ( dx+c \right ) \right ) }{8\,d}}-{\frac{{a}^{2}}{4\,d \left ( -1+\sec \left ( dx+c \right ) \right ) ^{2}}}-{\frac{7\,{a}^{2}}{4\,d \left ( -1+\sec \left ( dx+c \right ) \right ) }}+{\frac{17\,{a}^{2}\ln \left ( -1+\sec \left ( dx+c \right ) \right ) }{8\,d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.0235, size = 140, normalized size = 1.22 \begin{align*} -\frac{a^{2} \log \left (\cos \left (d x + c\right ) + 1\right ) - 17 \, a^{2} \log \left (\cos \left (d x + c\right ) - 1\right ) + 16 \, a^{2} \log \left (\cos \left (d x + c\right )\right ) - \frac{2 \,{\left (9 \, a^{2} \cos \left (d x + c\right )^{2} - 14 \, a^{2} \cos \left (d x + c\right ) + 4 \, a^{2}\right )}}{\cos \left (d x + c\right )^{3} - 2 \, \cos \left (d x + c\right )^{2} + \cos \left (d x + c\right )}}{8 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.83125, size = 531, normalized size = 4.62 \begin{align*} \frac{18 \, a^{2} \cos \left (d x + c\right )^{2} - 28 \, a^{2} \cos \left (d x + c\right ) + 8 \, a^{2} - 16 \,{\left (a^{2} \cos \left (d x + c\right )^{3} - 2 \, a^{2} \cos \left (d x + c\right )^{2} + a^{2} \cos \left (d x + c\right )\right )} \log \left (-\cos \left (d x + c\right )\right ) -{\left (a^{2} \cos \left (d x + c\right )^{3} - 2 \, a^{2} \cos \left (d x + c\right )^{2} + a^{2} \cos \left (d x + c\right )\right )} \log \left (\frac{1}{2} \, \cos \left (d x + c\right ) + \frac{1}{2}\right ) + 17 \,{\left (a^{2} \cos \left (d x + c\right )^{3} - 2 \, a^{2} \cos \left (d x + c\right )^{2} + a^{2} \cos \left (d x + c\right )\right )} \log \left (-\frac{1}{2} \, \cos \left (d x + c\right ) + \frac{1}{2}\right )}{8 \,{\left (d \cos \left (d x + c\right )^{3} - 2 \, d \cos \left (d x + c\right )^{2} + d \cos \left (d x + c\right )\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.52379, size = 258, normalized size = 2.24 \begin{align*} \frac{34 \, a^{2} \log \left (\frac{{\left | -\cos \left (d x + c\right ) + 1 \right |}}{{\left | \cos \left (d x + c\right ) + 1 \right |}}\right ) - 32 \, a^{2} \log \left ({\left | -\frac{\cos \left (d x + c\right ) - 1}{\cos \left (d x + c\right ) + 1} - 1 \right |}\right ) - \frac{{\left (a^{2} - \frac{12 \, a^{2}{\left (\cos \left (d x + c\right ) - 1\right )}}{\cos \left (d x + c\right ) + 1} + \frac{51 \, a^{2}{\left (\cos \left (d x + c\right ) - 1\right )}^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}}\right )}{\left (\cos \left (d x + c\right ) + 1\right )}^{2}}{{\left (\cos \left (d x + c\right ) - 1\right )}^{2}} + \frac{32 \,{\left (2 \, a^{2} + \frac{a^{2}{\left (\cos \left (d x + c\right ) - 1\right )}}{\cos \left (d x + c\right ) + 1}\right )}}{\frac{\cos \left (d x + c\right ) - 1}{\cos \left (d x + c\right ) + 1} + 1}}{16 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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